prove that (1+tan theta + sec theta) (1+cot theta- cosec theta) = 2
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Step-by-step explanation:
TAKING LHS
(1+tan Q + sec Q) (1+ot Q-cosc Q)
( 1+sinQ/cosQ+1/cosQ)(1+cosQ/sinQ-1/sinQ)
[(cosQ+sinQ+1)/cosQ][(sinQ+cosQ-1)/sinQ]
[(cosQ+sinQ+1)][(sinQ+cosQ-1)]/sinQcosQ
using identity
using identity(a + b) (a - b) = a^2- b^2
[(cosQ+sinQ)^2 -1^2]/sinQcosQ
(cos^2+sin^2Q+2cosQsinQ -1)/sinQcosQ
1 -1 + 2sinQcosQ/sinQcosQ
2sinQcosQ/sinQcosQ
= 2. = RHS
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