Question

Prove that 1+tan²A/1+SecA=SecA
(using LHS/RHS method)


Spam=Report Can anyone help me please☺
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Answer 1

Step-by-step explanation:

see answer in picture

hope this helps you

have a great day ahead

Answer 2

Step-by-step explanation:

1 + tan^2A/1 +secA

= 1 + (sec^2A-1)/1+secA

= 1 + {(secA-1)(secA+1)/(1+secA)}

=1 + secA - 1

=SecA

hope it will help you.