prove that (1/tan3x)+(tanx-1/cot3x)+cotx=cot4x
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1 / (tan(3x) - tan(x)) - 1/(cot(3x) - cot(x)) =>
1 / (sin(3x)/cos(3x) - sin(x)/cos(x)) - 1 / (cos(3x)/sin(3x) - cos(x)/sin(x)) =>
1 / ((sin(3x) * cos(x) - sin(x) * cos(3x)) / (cos(3x)cos(x))) - 1 / ((cos(3x)sin(x) - sin(3x)cos(x)) / (sin(x)sin(3x))) =>
cos(x)cos(3x) / sin(3x - x) - sin(x)sin(3x) / sin(x - 3x) =>
cos(x)cos(3x) / sin(2x) - sin(x)sin(3x) / sin(-2x) =>
cos(x)cos(3x) / sin(2x) + sin(x)sin(3x) / sin(2x) =>
(cos(3x)cos(x) + sin(3x)sin(x)) / sin(2x) =>
cos(3x - x) / sin(2x) =>
cos(2x) / sin(2x) =>
cot(2x)
1 / (sin(3x)/cos(3x) - sin(x)/cos(x)) - 1 / (cos(3x)/sin(3x) - cos(x)/sin(x)) =>
1 / ((sin(3x) * cos(x) - sin(x) * cos(3x)) / (cos(3x)cos(x))) - 1 / ((cos(3x)sin(x) - sin(3x)cos(x)) / (sin(x)sin(3x))) =>
cos(x)cos(3x) / sin(3x - x) - sin(x)sin(3x) / sin(x - 3x) =>
cos(x)cos(3x) / sin(2x) - sin(x)sin(3x) / sin(-2x) =>
cos(x)cos(3x) / sin(2x) + sin(x)sin(3x) / sin(2x) =>
(cos(3x)cos(x) + sin(3x)sin(x)) / sin(2x) =>
cos(3x - x) / sin(2x) =>
cos(2x) / sin(2x) =>
cot(2x)
karla1276:
cot4x?
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