prove that( 1+tanA-secA) ×(1+tanA+secA)=2tanA
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Step-by-step explanation:
(1 + tan A -sec A) (1+tan A+ sec A)
=>(1+ tan A)^2 - (sec^2A)
=>(1+tan^2A+2tanA)- (1+ tan^2A) [sec^2A=1+tan^2A]
=>1+tan^A+2tan A-1-tan^2 A
=>2 tan A Proved
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