Math, asked by arvind1062, 11 months ago

Prove that 100-100 divide by 100-100 is equal to 2

Answers

Answered by Anonymous
2

 \frac{100 - 100}{100 - 100}  \\   \frac{ {10}^{2}  -  {10}^{2} }{10(10 - 10)}  \\  {a }^{2} -  {b}^{2} = (a + b)(a - b) \\ \frac{(10 + 10)(10 - 10)}{10(10 - 10)}     \\ (10 - 10) \: will \: be \: canclled \\ so..... \\    \frac{10 + 10}{10}  \\  \frac{20}{10 } \\  = 2 \\ hence \: proved.....

Answered by яσѕнαη
5

\mathfrak{dear\;user  }

\mathfrak{question-}prove 100-100/100-100=2 ​

\mathfrak{here\:is\:the\:solution\:for \:the question  }

a^{2}-b^{2} =(a+b)(a-b)

= (100-100)\div  (100-100)=2

L.H.S

=(10^{2} -10^{2})\div10(10-10)

=(10+10)(10-10)\div10(10-10) cancel(10-10)from \:numerator \:and \:denominatior.

=10+10\div10

=20 \div 10

=2

R.H.S=2

\mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS  }10\:thanks\:and \:brainlist

\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}

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