Question

prove that:


10x∧2+ 15x+63/5x∧2-25x+12=2x+3/x-5

Answer 1

Answer:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

10*x^2+15*x+63/5*x^2-25*x+12-(2*x+3/x-5)=0

Step by step solution :

Step 1 :

3

Simplify —

x

Equation at the end of step 1 :

63 3

(((((10•(x2))+15x)+(——•(x2)))-25x)+12)-((2x+—)-5) = 0

5 x

Step 2 :

Rewriting the whole as an Equivalent Fraction :

2.1 Adding a fraction to a whole

Rewrite the whole as a fraction using x as the denominator :

2x 2x • x

2x = —— = ——————

1 x

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2x • x + 3 2x2 + 3

—————————— = ———————

x x

Equation at the end of step 2 :

63 (2x2+3)

(((((10•(x2))+15x)+(——•(x2)))-25x)+12)-(———————-5) = 0

5