Prove that 2+3√3 is irrational number if it is given that √3 is irrational number
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Given:
3+2√3
To Find :
3+2√3 is an irrational number
Solution :
First, shall we prove that √3 is an irrational number.
So,
Let us assume that√3 is an rational number, a and b are co prime numbers and b ≠ 0.
√3 = a/b
b√5 = a
Square on both sides:
(b√3)² = a²
3b²= a² -------(★)
b²=a²/3
•°• 3 is an prime number
If 3 divides a² then 3 divides a also
3 is a factor of a ------(1)
now,
assume that a = 3c in (★)
3b²=(3c)²
3b²=9c²
c²=b²/3
b² is divisible by 3
•°• 3 is a factor of b -------(2)
From (1) and (2)
a and b are not co prime number because HCF is 1.
So, a and b is not a rational number, our assumption is wrong.
So, √3 is irrational number.
now
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