Prove that √2-3√5 is an irrational number
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Assume √2-3√5 be a rational no
therefore √2-3√5=a/b
hence √5=a-√2b/3b
therefore a-√2b/3b is a rational no
therefore √5 is a rational no
but we know that √5 is a irrational no
therefore our assumption was wrong that √2-3√5 is a rational no
therefore √2-3√5 is a irrational no.
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