Question

prove that 2✓3-7 is an irrational. if you tell the correct answer I will mark as brilliant I promise​

Answer 1

Answer:

let 2√3-7 be rational.

then, 2√3-7 =a/b (where a& b are co prime and b is not equal to 0)

2√3-7=a/b

=> 2√3=a/b+7

=>2√3=a+7b/b

=>√3=a+7b/2b

here, a+7b/2b is rational so, √3 is also rational

but this contradicts the fact that √3 is Irrational.

this, our assumption is wrong

2√3-7 is not rational

•

• • 2√3-7 is Irrational