Prove that 2+√3 is irrational
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Answered by
582
let us assume 2+√3 as rational.
⇒2+√3=a/b
∴2-a/b=-√3 or √3=a/b-2
⇒√3=a/b-2
√3=a-2b/b
∵a and b are positive integers
∴a-2b/b is rational
⇒√3 is rational
but we know that √3 is irrational
∴⇒2+√3 is irrational
⇒2+√3=a/b
∴2-a/b=-√3 or √3=a/b-2
⇒√3=a/b-2
√3=a-2b/b
∵a and b are positive integers
∴a-2b/b is rational
⇒√3 is rational
but we know that √3 is irrational
∴⇒2+√3 is irrational
Denita1:
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Answered by
163
Answer:
let us assume 2+√3 as rational.
⇒2+√3=a/b
∴2-a/b=-√3 or √3=a/b-2
⇒√3=a/b-2
√3=a-2b/b
∵a and b are positive integers
∴a-2b/b is rational
⇒√3 is rational
but we know that √3 is irrational
∴⇒2+√3 is irrational
Step-by-step explanation:
let us assume 2+√3 as rational.
⇒2+√3=a/b
∴2-a/b=-√3 or √3=a/b-2
⇒√3=a/b-2
√3=a-2b/b
∵a and b are positive integers
∴a-2b/b is rational
⇒√3 is rational
but we know that √3 is irrational
∴⇒2+√3 is irrational
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