Prove that
√2 +
√3 is irrational
Answers
Answer:
The answer can be given as below.
Step-by-step explanation:
here is your answer mate:
Let us assume that √2 is rational. then there exists integers a and b such that
√2 = a/b (where a and b are co prime)
squaring on both sides
2 = a^2/b^2
2b^2 = a^2 - (i)
2 divides a^2
thus 2 divides a - (ii)
a = 2c
a^2 = 4c^2
2b^2 = 4c^2 - from (i)
b^2 = 2c^2
2 divides b^2
thus 2 divides b -(iii)
from ii and iii
2 is the common factor of a and b
but that is not possible as a and b are co prime
thus our assumption is wrong
thus √2 is irrational - iv
let us assume that √2 + √3 is rational
√2 + √3 = a/b (where a and b are co prime)
√3 = a/b - √2
squaring on both sides
3= a^2/b^2 - 2a√2/b + 2
a^2/b^2 - 1 = 2a√2/b
a^2 - b^2/2ab = √2
since a and b are integers
LHS is rational
thus √2 should be rational
but we know that √2 is irrational
hence our assumption is wrong
√2 + √3 is irrational
hope this helps you buddy
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