prove that 2^30+2^29+2^28/2^31+2^30-2^29=7/10
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2^30+2^29+2^28/2^31+2^30-2^29
=2^-1+2^-1-2^-1
=-2+(-2)-(-2)
=-2-2+2
=-2
=2^-1+2^-1-2^-1
=-2+(-2)-(-2)
=-2-2+2
=-2
Answered by
0
Let 2^28 be x.
Then,
2×2×x+2×x+x/2×2×2×x+2×2×x-x=7/10
=7x/10x
=7/10
HENCE PROVED
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