Prove that 2 a s=v2-u2 in physics
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We can check the correctness of equation by Dimensional Analysis.
Equation: V²-U²=2as
where V=u=velocities = Dimension=LT⁻¹
a= acceleration=ΔV/T=LT⁻¹/T=LT⁻²
S=Distance=L
R.H.S=2as=2x[LT⁻²]x[L]=[L²T⁻²]
L.H.S=v²-u²=[LT⁻¹]²=[L²T⁻²]
Therefore L.H.S=R.H.S
Hence we can say equation is correct
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