Solve the following equations:-
√3x + √2y = √3
√5x + √3y = √3
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Hi ,
√3x - √2y = √3 -----( 1 )
√5x + √3y = √3 ----( 2 )
Do [ ( 1 ) × √5 - ( 2 ) × √3 ]
√15x - √10y = √15
√15x + 3 y = 3
_______________
-y( 3 + √10 ) = √15 - 3
Therefore ,
y = ( √15 - 3 )/[ -( 3 + √10 ) ]
y = ( 3 - √15 )/( 3 + √10 )
Do [ ( 1 ) × √3 + ( 2 ) × √2 ],
3x - √6 y = 3
√10 x + √6 y = √6
_________________
( 3 + √10 )x = 3 + √6
x = ( 3 + √6 )/( 3 + √10 )
Therefore ,
x = ( 3 + √6 )/( 3 + √10 ) ,
y = ( 3 - √15 )/( 3 + √10 )
I hope this helps you.
: )
√3x - √2y = √3 -----( 1 )
√5x + √3y = √3 ----( 2 )
Do [ ( 1 ) × √5 - ( 2 ) × √3 ]
√15x - √10y = √15
√15x + 3 y = 3
_______________
-y( 3 + √10 ) = √15 - 3
Therefore ,
y = ( √15 - 3 )/[ -( 3 + √10 ) ]
y = ( 3 - √15 )/( 3 + √10 )
Do [ ( 1 ) × √3 + ( 2 ) × √2 ],
3x - √6 y = 3
√10 x + √6 y = √6
_________________
( 3 + √10 )x = 3 + √6
x = ( 3 + √6 )/( 3 + √10 )
Therefore ,
x = ( 3 + √6 )/( 3 + √10 ) ,
y = ( 3 - √15 )/( 3 + √10 )
I hope this helps you.
: )
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