prove that √2 is an irrational number. Hence show that 3-√2 is an irrational number
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take 3-underoot 2 bt rational as well as co primes
since
3-underrot 2 = a/b
underoot 2 = 3 - a/b
3- a/b is rational no.
bt this contradict the fact that underoot 3 is irrsrional coz they are equal
hence we can say that our supposition is wrong and 3 - undrroot 2 is irrational no.
since
3-underrot 2 = a/b
underoot 2 = 3 - a/b
3- a/b is rational no.
bt this contradict the fact that underoot 3 is irrsrional coz they are equal
hence we can say that our supposition is wrong and 3 - undrroot 2 is irrational no.
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