Question

prove that (2a, 6a) and(2a+√3+5a) are the vertices of equilateral triangle. ​

Answer 1

ANSWER

PROOF :-

AB=  (2a−2a)  2 +(6a−4a)  2

 

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=2a AC=  (2a−(2a+  3 a))  2 +(4a−5a)  2

 

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=  3a  2 +a  2

 

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=2a BC=  (2a+  3  a−2a)  2  +(6a−5a)  2

 

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=2a

AB=BC=AC=2a All sides are equal.

Hence, It is an equilateral triangle.