Prove that
2cos^(2)x + 3sinx= 0
GarryRich:
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Answer:
x = 30° + 360°k OR x = 150° + 360°k, where k is an integer.
Step-by-step explanation:
Assuming you mean solve this equation (it's not a true identity to be proved)...
2 cos² x + 3 sin x = 0
=> 2 ( 1 - sin² x ) + 3 sin x = 0
=> 2 - 2 sin² x + 3 sin x = 0
=> 2 sin² x - 3 sin x - 2 = 0
=> ( 2 sin x + 1 ) ( sin x - 2 ) = 0
=> sin x = -1/2 OR sin x = 2
But sin x cannot be greater than 1, so
sin x = -1/2
=> x = 30° + 360°k OR x = 150° + 360°k, where k is an integer.
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