prove that:2cosQ+2/1+cot^Q=2.
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Step-by-step explanation:
Step-by-step explanation:
2cos^2 theta + 2/1 + cot^2 theta = 2
2 cos^2 theta + 2/ cosec^2 theta = 2
( 1 + cot^2 theta is = cosec^2 theta)
2cos^2 theta + [1/cosec^2 theta ×2]=2
(As 1/cosec^2 theta = sin^2 theta)
2cos^2 theta + [sin^2 theta ×2] = 2
2cos^2 theta + 2sin^2 theta = 2
(Now we take 2 as common)
2[ cos^2 theta + sin^2 theta] = 2
(As cos^2 theta + sin^2 theta = 1)
2 [1] = 2
2 = 2
LHS = RHS
Hence proved.
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