Prove that 2tan50-tan70+tan20=0
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Step-by-step explanation:
block of mass m is placed on smooth inclined plane of incilation tetha with the horizontal. The dorce exerted by the plane on the block
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Step-by-step explanation:
tan 50=1.19175359259
Therefore, 2( tan50)=2.38350718519
tan 70=2.74747741945
2tan50-tan70=
2.38350718519-2.74747741945
= - 0.36397023426
tan 20 = 0.36397023426
2*(tan 50)- tan 70 + tan 20=
0.36397023426 - 0.36397023426
=0
LHS=RHS
Hence Proved
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