Question

prove that 2v1v2/v1+v2 when a moving body travels distance S with constant speed v1 and S with uniform speed v2

Answer 1

Answer: prove that 2v1v2 / V1 + V2 when a moving body travels distance as with constant speed V1 and as with constant speed V 2

Answer 2

Concept Introduction:-

It could take the shape of a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that $2v_1v_2/v_1+v_2$ when a moving body travels distance $S$ with constant speed $v_1$ and $S$ with uniform speed $v_2$

To Find:-

We have to prove that $2v_1v_2/v_1+v_2$

Solution:-

According to the problem

Average speed $=\frac{\text { Total distance traveled }}{\text { Total Time taken }}$

$\Rightarrow \text { Av.speed }=\frac{\mathrm{S}+\mathrm{S}}{\left(\frac{\mathrm{S}}{\mathrm{v}_{1}}+\frac{\mathrm{S}}{\mathrm{v}_{2}}\right)}$

$\Rightarrow \text { Av.speed }=\frac{2 \mathrm{~S}}{\mathrm{~S}\left(\frac{\mathrm{v}_{1}+\mathrm{v}_{2}}{\mathrm{v}_{1} \mathrm{v}_{2}}\right)}$

$\Rightarrow \text { Av.speed }=\frac{2 \mathrm{v}_{1} \mathrm{v}_{2}}{\mathrm{v}_{1}+\mathrm{v}_{2}}$

Final Answer:-

The correct answer is that $2v_1v_2/v_1+v_2$ is proved.

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