Question

prove that (√3+1)(3-cot30°)=tan³60°-2sin60°​

Answer 1

Step-by-step explanation:

L.H.S.=(√3+1)(3−cot30∘)=(√3+1)(3−√3)

=(√3+1)(√3−1)√3=√3(3−1)=2√3.

R.H.S.=tan3(60∘)−2sin60

=(√3)3−2(√32)=3√3−√3=2√3

therefore LHS=RHS

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Answer 2

Answer:

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Step-by-step explanation:

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