Prove that 3+2√5 is irrational.
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Prove 3+2√5 is irrational.
→ let take that 3+2√5 is rational number
→ so, we can write this answer as
⇒3+2√5 = a/b
Here a & b use two coprime number and b
is not equal to 0
, => √5 = (p/q) -3
=> √5 = (p-3q)/q
Here, in RHS , numerator is the difference of 2 integers, which always remains an integer. & denominator is also an integer, not = 0.
=> RHS is a rational number ( as, all the conditions for being a rational number, have been satisfied )
But LHS is an irrational number. ( by theorem, √5 is an irrational number)
=> LHS not = RHS
=> our assumption (that 3+√5 is a rational number) is wrong.
Hence, 3+√5 is an irrational number
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