Question

Prove that 3√2/7 is irrational​

Answer 1

$\huge \tt \overline{hlw \: mate \star}$

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Lets assume that 2√3-7 is rational

Let ,

2√3-7 = r , where r is rational

2√3 = r + 7

√3 = r + 7/2

Here ,

RHS is purely rational , whereas , LHS is irrational

This is a contradiction.

Hence ,

our assumption was wrong.

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Therefore ,

2√3-7 is an irrational number

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Answer 2

let 3√2/7 be rational

3√2/7=p/q where p and q are coprime