Prove that √3/2 is an irrational number.
Answers
Answered by
0
Step-by-step explanation:
Let us assume, to the contrary, that 3
2 is rational. Then, there exist co-prime positive integers a and b such that 3
2 = b
a⇒
2 = 3b
a⇒
2 is rational
...[∵3,a and b are integers∴
3b a is a rational number]
This contradicts the fact that
2 is irrational.
So, our assumption is not correct.
Hence, 3
2 is an irrational number.
Answered by
3
Answer:
Let √3 / 2 be rational, so, it can be expressed as p/q where, p and q are co prime numbers.
√3 / 2 = p / q
or, √3 = 2p / q
Since, p , q , and 2 are rational so √3 is rational.
This contradict the fact that √3 is irrational.
So, √3 / 2 is irrational.
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