Question

prove that 3+√2 is irrational

Answer 1

becz I cannot write in the form p/q

Answer 2

let us assume ,to our contradiction that 3+√2 is rational
so it can be written in form a/b where b≠0 and they are Co prime ( no common factor except 1)
so 3+√2=a/b
√2=a/b-3
√2=(a-3b)/b
here a, b and 3 are integers so √2 is rational which contradict the fact that it is irrational so
3+√2 is irrational