Math, asked by namit80, 11 months ago

prove that 3-3root7 is an irrational no​

Answers

Answered by Anonymous
4

3 - 3√7

Let us take on contrary that 3 root 7 is rational. then there exist two co prime numbers a and b such that 

3root 7 = a/b

=> root 7 = a / 7b

now LHS is an irrational no. whereas RHs is rational

this contradiction has arised due to our wrong assumption in beginning 

therefore 3 root 7 is an irrational number

HOPE IT WILL HELP YOU


Annarhysa: that is actually the wrong method. initially I also thought to do it in the same way
Similar questions