Prove that 3+5√2 is an irrational numbers
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Answered by
1
Answer:
Given: 3 + 2√5
To prove: 3 + 2√5 is an irrational number.
Proof:
Let us assume that 3 + 2√5 is a rational number.
So it can be written in the form a/b
3 + 2√5 = a/b
Here a and b are coprime numbers and b ≠ 0
Solving 3 + 2√5 = a/b we get,
=>2√5 = a/b – 3
=>2√5 = (a-3b)/b
=>√5 = (a-3b)/2b
This shows (a-3b)/2b is a rational number. But we know that But √5 is an irrational number.
so it contradictsour assumption.
Our assumption of 3 + 2√5 is a rational number is incorrect.
3 + 2√5 is an irrational number
Hence proved
Step-by-step explanation:
Hope It Helps You:)
Answered by
1
Step-by-step explanation:
rational no × irrational =irrational
5 × √2 = irrational
rational no + irrational = irrational
3 + 5√2 = irrational
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