prove that 3-5√2 is irrational?
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Step-by-step explanation:
To prove: 3 + 2√5 is an irrational number. Proof: Let us assume that 3 + 2√5 is a rational number. This shows (a-3b)/2b is a rational number.
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⫷❥AN SWER⫸⋆⤵️⤵️
Step-by-step explanation:
Let us assume that 3-5√2 is a rational number.
So it can be written in the form a/b
3-5√2 = a/b
Here a and b are coprime numbers and b ≠ 0
Solving 3-5√2 = a/b we get,
=>5√2 = a/b – 3
=>5√2 = (a-3b)/b
=>√2 = (a-3b)/5b
This shows (a-3b)/5b is a rational number. But we know that But √2 is an irrational number.
so it contradictsour assumption.
Our assumption of 3-5√2 is a rational number is incorrect.
3-5√2 is an irrational number
Hence proved
☺️☺️
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