Math, asked by sarbajitsonowal1974, 1 month ago

prove that 3-5√2 is irrational?

Answers

Answered by vermanushka7487
2

Step-by-step explanation:

To prove: 3 + 2√5 is an irrational number. Proof: Let us assume that 3 + 2√5 is a rational number. This shows (a-3b)/2b is a rational number.

Answered by alisha1130
4

Answer:

⫷❥AN SWER⫸⋆⤵️⤵️

Step-by-step explanation:

Let us assume that 3-5√2 is a rational number.

So it can be written in the form a/b

3-5√2 = a/b

Here a and b are coprime numbers and b ≠ 0

Solving 3-5√2 = a/b we get,

=>5√2 = a/b – 3

=>5√2 = (a-3b)/b

=>√2 = (a-3b)/5b

This shows (a-3b)/5b is a rational number. But we know that But √2 is an irrational number.

so it contradictsour assumption.

Our assumption of 3-5√2 is a rational number is incorrect.

3-5√2 is an irrational number

Hence proved

☺️☺️

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