Question

prove that 3√5 +7 is irrational, given that √5 is irrational number​

Answer 1

Answer:

Let us assume to the contrary that 3√5-7 is a rational no.

Such That ,

3√5-7=p/q {where, p and q are integers having no common factors}.

3√5=p/q+7

3√5=.p+7q/q

√5= p+7q/3q

where , √5 and p+7q/3q are rational numbers.

But this contradicts the fact that √5 is irrational.

Therefore,3√5-7 is an irrational no.

Answer 2

Step-by-step explanation:

√5 kisi bhi number ka perfect root nhi hota that's why 3√5+7 is irrational

and

√5 is also a irrational number

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