Prove
that
3+ √5 as irrational
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Answered by
1
Answer:
Let us asume that 3+ √5 is rational ,
Where 3+ √5 =a\b
A and B are co prime numbers
3+ √5 =a\b
√5=a\b-3
√5=a-3b\b
a-3b\b is rational ..but we know that √5 is irrational
therefore our assumption is wrong
3+ √5 is irrational
Answered by
0
let the 3+√5 is rational
3+√5 =a/b here a and b have no common factor
√5 = a/b-3
√5 = a-3b/b
here we get that a-3b/b is rational no but we know the fact that √5 is irrational no
this arises from 3+√5
hence our assumption is wrong
hence 3+√5 is irrational no
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