Prove that (3 + √5) is a irrestional number.
Answers
Answered by
1
let us assume to the contrary that (3+√5) is rational.
i.e. we can find co prime a/b
(3+√5)=a/b
= √5= a/b-3
since a , b, and 3 are integers ,. they are rational and since √5 is rational,
but , this contradicts the fact that √5 is irrational,. so (3+√5) is irrational
i.e. we can find co prime a/b
(3+√5)=a/b
= √5= a/b-3
since a , b, and 3 are integers ,. they are rational and since √5 is rational,
but , this contradicts the fact that √5 is irrational,. so (3+√5) is irrational
nickroker:
thanks
Similar questions