Question

Prove that 3 + √5 is an irrational number​

Answer 1

Answer:

proved bro

Step-by-step explanation:

Let us assume that 3+  

5

​  

 is a rational number.

Now,

3+  

5

​  

=  

b

a

​  

 [Here a and b are co-prime numbers]

5

​  

=[(  

b

a

​  

)−3]

5

​  

=[(  

b

a−3b

​  

)]

Here, [(  

b

a−3b

​  

)] is a rational number.

But we know that  

5

​  

 is an irrational number.

So, [(  

b

a−3b

​  

)] is also a irrational number.

So, our assumption is wrong.

is an irrational number.

Answer 2

Answer:

......idk ......................