Prove that √3-√5 is an irrational number
Answers
Answered by
1
Answer:
To prove that 3+√5 is an irrational number, first assume it to be a rational number. ... As both p and q are integers, so p−3q is also an integer. As q is not equal to 0, p−3qq is a rational number. ⇒√5 = p−3qq is also a rational number
Answered by
1
Answer:
Step-by-step explanation:
irrational numbers cannot be expressed as the ratio of two integers.
√3 = 1.73 , √5= 2.24
Therefore,
√3-√5 = 1.73 - 2.24 = - 0.51
Similar questions