Prove that 3√5 is irrational.
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Answered by
0
Answer:
Let us assume that 3−
5
is a rational number
Then. there exist coprime integers p, q,q
=0 such that
3−
5
=
q
p
=>
5
=3−
q
p
Here, 3−
q
p
is a rational number, but
5
is a irrational number.
But, a irrational cannot be equal to a rational number.
This is a contradiction.
Thus, our assumption is wrong.
Therefore 3−
5
is an irrational number.
Answered by
0
Answer:all rational numbers could be written in p/q form but it could not so it is irrational.
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