Question

prove that 3+√5 is irrational ​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let assume that 3 + √5 is a rational no.

Now ,

3 + √5 = a/b [ here, a & b are co-prime no. ]

=> √5 = a/b - 3

=> √5 = (a - 3b)/b

Here,

( a - 3b )/b is a rational no.

But,

we know that √5 is an irrational number.

So,

(a - 3b)/b is also an irrational no.

So, Our assumption is wrong .

Hence,

3 - √5 is an irrational no.

Proved ✓✓✓

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