Math, asked by anubhavrajput2006, 9 months ago

Prove that ³√5 is irrational

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Answered by ak94858538
0

Answer:

So 3+2√5 = a/b where a,b are integers and are co primes and b is not equal to 0. => √5 = (a-3b)/2b. In this since,b,3,2 are integers a-3b and 2b are integers and 2b is not equat to 0. ... => √5 is rational which is a contradiction since √5 is irrational.

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Answered by KRPS500
2

Prove that 3+2√5 is irrational?

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