Prove that ³√5 is irrational
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So 3+2√5 = a/b where a,b are integers and are co primes and b is not equal to 0. => √5 = (a-3b)/2b. In this since,b,3,2 are integers a-3b and 2b are integers and 2b is not equat to 0. ... => √5 is rational which is a contradiction since √5 is irrational.
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Prove that 3+2√5 is irrational?
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