Question

prove that √3+√5 is irrational ​

Answer 1

Answer:

so

Step-by-step explanation:

$\sqrt{5 \: } \\ is \: a \: irrational \: number$

Answer 2

Answer:

hope my answer will help you

Step-by-step explanation:

let us assume √3+√5 are rational no.

then they exist 2 no. such that

√3+√5 = a/b

√5 = a/b - √3

squaring on both sides

5 = a²/b² -2a√3/b +3

2 +2a√3/b = a²/b²

2+√3 = a²/b² x b/2a

2+√3 = a/2b

since a/2b is a rational no the 2+√3 is also a rational no.

but it is false because we know √3 is irrational no.

this is because of our wrong assumption that is

√3+√5 are rational no.

so √3+√5 are irrational no.