Prove
that
√3+√5 is
irrational
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Step-by-step explanation:
just replace the numbers
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Answer:
Let assume that √3+√5 is a irrational number.
⇒√3+√5=a/b[ where a,b are integers]
⇒S.O.B.S
- (√3+√5)²=(a/b)²
- (√3)²+(√5)²+2(√3)(√5)=a²/b²
- 3+5+2√15=a²/b²
- 8+2√15=a²/b²
- 2√15=a²/b²-8
- 2√15=5b²-a²/b²
- √15=5b²-a²/2b²
5b²-a²/2b² is a rational number and √15 is a rational number.But contradicts that √15 is a irrational number.Hence √3+√5 also irrational number.
Hence your assumption is wrong.
hence proved √3+√5 is a irrational number.
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