Math, asked by muneendranamdev, 2 months ago

Prove
that
√3+√5 is
irrational​

Answers

Answered by ps9576240
0

Step-by-step explanation:

just replace the numbers

Attachments:
Answered by Anonymous
0

Answer:

Let assume that 3+5 is a irrational number.

√3+√5=a/b[ where a,b are integers]

⇒S.O.B.S

  • (√3+√5)²=(a/b)²
  • (√3)²+(√5)²+2(√3)(√5)=a²/b²
  • 3+5+2√15=a²/b²
  • 8+2√15=a²/b²
  • 2√15=a²/b²-8
  • 2√15=5b²-a²/b²
  • √15=5b²-a²/2b²

5b²-a²/2b² is a rational number and 15 is a rational number.But contradicts that 15 is a irrational number.Hence 3+5 also irrational number.

Hence your assumption is wrong.

hence proved 3+5 is a irrational number.

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