Prove that.√3√5and√7 is irrational.
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Prove that 3 √ 5'7 is irrational
3√5-7=p/q {where, p and q are integers having no common factors}. where , √5 and p+7q/3q are rational numbers. But this contradicts the fact that √5 is irrational. Therefore,3√5-7 is an irrational no
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