prove that 3-5root 2 is irrational
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let us assume, to contrary,that 3-5√2 is rational
i.e. , we can find co prime a and b (b≠0) such that 3-5√2=a/b
therefore, 3-a/b=5√2
rearranging this equation we get 5√2=3-a/b
since a and b are integers ,we get 3-a/b is rational , and so 5√2is rational
but it contradicts the fact that 5√2 is irrational.
this contradiction has arisen because of our incorrect assumption that 3-5√2 is rational.
so, we conclude that 3-5√2 is irrational
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