Question

Prove That 3+6√2 is Irrational.
(CLASS 10)​

Answer 1

Step-by-step explanation:

Let 3 + 6√2 be a rational number (say r)

∴ 3 + 6√2 = r

⇒ 6√2 = r-3

⇒√2 = (r - 3) / 6  --1

According to equation 1,

√2 is a rational number ( ∵ r is a rational number)

This contradicts the fact that √2 is irrational

Therefore, our assumption is wrong

Hence, 3 + 6√2 is an irrational number.

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