Question

prove that 3√6 inrational number​

Answer 1

Hey mate here is your answer➡➡➡➡➡

Explanation:-

let 3√6 be a rational number then ,

3√6=a/b

here a and b are co primes

$\sqrt{6} = a \div 3b$

A and B are integers so then 3√6 is a rational number but it contradicts our hyporthesis that √6 is irrational .

so 3√6 is an irrational number

hence proved

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