Question

Prove that 3 √7 is an irrational number.​

Answer 1

Answer:

Let if possible

$3 \sqrt{7} \: is \: irrational$

$3 \sqrt{7} = \frac{a}{b} \\ \sqrt{7} = \frac{a - 3}{b}$

it means

$\sqrt{7}$

is rational but this is a contruction became we known that

$\sqrt{7} \: is \: irrational$

.So, our supposition is wrong.

Hence

$3 \sqrt{7} \: is \: irrational$

Step-by-step explanation:

ok