Prove that 3√7 is irrational
Answers
Answered by
77
Hii friend,
If possible , let 3✓7 be rational Number. Then 3✓7 is rational , 1/3 is rational.
=> (1/3 × 3✓7) is rational . [ Because product of two rationals is rational]
=> ✓7 is rational.
This contradicts the fact that ✓7 is irrational.
This contradiction arises by assuming that 3✓7 is rational.
Hence,
3✓7 is irrational...... PROVED......
HOPE IT WILL HELP YOU.... :-)
If possible , let 3✓7 be rational Number. Then 3✓7 is rational , 1/3 is rational.
=> (1/3 × 3✓7) is rational . [ Because product of two rationals is rational]
=> ✓7 is rational.
This contradicts the fact that ✓7 is irrational.
This contradiction arises by assuming that 3✓7 is rational.
Hence,
3✓7 is irrational...... PROVED......
HOPE IT WILL HELP YOU.... :-)
Answered by
55
Hey!!!!
Let 3/√7 be a rational number
3/√7=p/q
√7=p/3q(Integer/interger)
But √7 is irrational number
Hence our contradiction was wrong
3/√7 is irrational number
hence proved
hope it helps u!!!!!!!!!
Let 3/√7 be a rational number
3/√7=p/q
√7=p/3q(Integer/interger)
But √7 is irrational number
Hence our contradiction was wrong
3/√7 is irrational number
hence proved
hope it helps u!!!!!!!!!
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