prove that √3 ia irrational number
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let √3 be rational
√3 = p/q
p = q√3
p² = q² * 3
thus, 3 is a factor of p²
and 3 is a factor of p also
let p = 3k
we know that p = q√3
(3k)² = (q√3)²
9k² = 3q²
3k² = q²
thus, 3 is a factor of q² and q also.
p and q are not co-prime
Thus, √3 is irrational
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