Question

Prove that 3 into square of altitude of triangle is equal to 4 into square of any side in an equilateral triangle.

Answer 1

Answer:

let the length of altitud

Answer 2

${\huge{\bold{\blue{HeyMate}}}}$

Let the triangle ABC

and AD it's altitude

then through the Pythagoras theorem we can find that

$altitude = \frac{\sqrt{3}a}{2}$

where a is any side of the triangle

Now,

On squaring both sides

$AD^2 = (\frac{\sqrt{3}a}{2})^2$

$AD^2 = \frac{3a^2}{4}$

$4B^2 = 3a^2$

Since we already stated that a is any side of equilateral triangle as all the sides are same

so,

$4AD^2 = 3AB^2$

Hence Proved........

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Hope you get your answer mate

#RadheRadhe