prove that √3 is an irrational number .
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Answer:
Step-by-step explanation:
Let us assume that root 3 is rational.
Root 3 = a/b where a and b are integers and coprimes.
Root 3 * b = a
Square LHS and RHS
3b2 = a2
b2 = a2/3
Therefore 3 divides a2 and 3 divides a.
Now take ,
a = 3c
Square ,
a2 = 9c2
3b2 = 9c2
b2/3 = c2
Therefore 3 divides b2 and b.
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