Prove that 3 is an irrational number.
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Step-by-step explanation:
IT IS A ROOT 3
Let P and Q be the points of trisection of AB.
Then, P divides AB in the ratio 1:2.
So, the coordinates of P are
P(1×4+2×(−5)1+2,1×(−3)+2×61+2),i.e.,P(−2,3)
Also, Q divides AB in the ratio 2:1.
So, the coordinates of Q are
Q(2×4+1×(−5)2+1,2×(−3)+1×62+1),i.e.,Q(1,0)
Hence, the points of trisection of AB are P(-2, 3) and Q(1, 0).
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