Prove that √3 is an irrational number. Hence, show that 2÷5√3 is an irrational number
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Let 2/5√3 is rational.
Then, it can be written in the form of a/b where a and b are +ve integers and b is not equal to zero
therefore,
2/5√3= a/b => 2b= 5√3a
=> 2b/5a= √3
Clearly LHS is rational and rhs is irrational.
So contradiction arises.
Hence, the given no. Is irrational
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