Prove that 3 log 2 + log 5 = log 40.
Answers
Answered by
1
Answer:
3log2+log5=log2^3+log5
=log(2^3*5)
=log(8*5)=log40
Answered by
0
Answer:
let us take RHS
3 log2 + log 5 = log 2³ + log 5
( m log n = log n m )
= log 8 + log 5
= log (8×5)
= log 40
= RHS
= 3 log 2 + log 5, = log 40
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